''' 
 197) Текстовый файл 24-197.txt содержит строку из заглавных латинских букв 
 X, Y и Z, всего не более чем из 106 символов. 
 Определите максимальное количество идущих подряд троек символов ZXY или ZYX. 
 ''' 
 f = open("files/5.txt") 
 s = f.readline() 
 f.close() 
 count = maxcount = 0 
 stroka="" 
 maxstroka = "" 
 last_ch='' 
 for i in range(len(s)-1): 
     if (count % 3 == 0 and s[ i] == "Z") or \ 
        (count % 3 == 1 and ((s[ i]+s[i+1] == "XY") or (s[ i]+s[i+1] == "YX"))) or \ 
        (count % 3 == 2 and s[ i] in "XY" and s[i+1]=="Z" ): 
         count += 1 
         stroka += s[ i] 
         if count > maxcount: 
             maxstroka = stroka 
             maxcount = count 
             last_ch = s[i+1] 
     else: 
         count = 0 
         stroka = "" 
 maxcount += 1 
 maxstroka += last_ch 
 print(maxcount) 
 print(maxstroka) 
 # 83 
 # ZXYZXYZYXZXYZYXZYXZXYZXYZYXZXYZXYZXYZXYZYXZYXZYXZXYZXYZYXZXYZXYZYXZYXZXYZYXZXYZYXZY 
  
 # ZXYZXYZYXZXYZYXZYXZXYZXYZYXZXYZXYZXYZXYZYXZYXZYXZXYZXYZYXZXYZXYZYXZYXZXYZYXZXYZYX 
 # если убрать хвост то 81 
 # в ответе 28 => всего символов 28*3=84 - противоречие 
 #---------------------------------------------- 
  
 count = maxcount = 0 
 stroka = maxstroka = "" 
 flag = "" 
  
 for i in range(len(s)): 
     if (flag != ""): 
         if (s[ i] == flag[count%3]): 
             count += 1 
             stroka += s[ i] 
             if count>maxcount: 
                 maxstroka = stroka 
                 maxcount = count 
         else: 
             flag = "" 
             count = 0 
             stroka = "" 
     elif (s[ i] == "Z"): 
         if (s[i+1] + s[i+2] == "XY"): 
             flag = "ZXY" 
             count+=1 
         elif (s[i+1] + s[i+2] == "YX"): 
             flag = "ZYX" 
             count += 1 
         stroka = "Z" 
  
 print(maxcount) 
 print(maxstroka) 
 # 40 
 # ZXYZXYZXYZXYZXYZXYZXYZXYZXYZXYZXYZXYZXYZ 
 # тут тем более 
 

f = open("files/5.txt") 
 s = f.readline() 
 f.close() 
 count = maxcount = 0 
 stroka="" 
 maxstroka = "" 
 last_ch='' 
 for i in range(len(s)-1): 
     if (count % 3 == 0 and s == "Z") or \ 
        (count % 3 == 1 and ((s+s[i+1] == "XY") or (s+s[i+1] == "YX"))) or \ 
        (count % 3 == 2 and s in "XY" and s[i+1]=="Z" ): 
         count += 1 
         stroka += s 
         if count > maxcount: 
             maxstroka = stroka 
             maxcount = count 
             last_ch = s[i+1] 
     else: 
         count = 0 
         stroka = "" 
 maxcount += 1 
 maxstroka += last_ch 
 print(maxcount) 
 print(maxstroka) 
 # 83 
 # ZXYZXYZYXZXYZYXZYXZXYZXYZYXZXYZXYZXYZXYZYXZYXZYXZXYZXYZYXZXYZXYZYXZYXZXYZYXZXYZYXZY 
  
 # ZXYZXYZYXZXYZYXZYXZXYZXYZYXZXYZXYZXYZXYZYXZYXZYXZXYZXYZYXZXYZXYZYXZYXZXYZYXZXYZYX 
 # если убрать хвост то 81