e = '02468' 
 o = '13579' 
 n = 0 
 for s in range(100000,1000000): 
     x = list(str(s)) 
     if ((x[0] in e and x[2] in e and x[4] in e and x[1] in o and x[3] in o and x[5] in o)\ 
         or (x[0] in o and x[2] in o and x[4] in o and x[1] in e and x[3] in e and x[5] in e))\ 
         and (x == sorted(x,reverse = True)): 
             #print(s) 
             n += 1 
 print(n)

 from itertools import permutations 
  
 def f(p,q): 
     n = 0 
     for a, c, e in permutations(p,3): 
         for b, d, f in permutations(q,3): 
             x = list(a+b+c+d+e+f) 
             if a != '0' and x == sorted(x,reverse = True): 
                 n += 1 
     return n 
  
 even = '02468' 
 odd  = '13579' 
  
 print(f(even,odd)+f(odd,even))